Originally Posted by
parrothead
Well, I think a lot of people have stated that 10% is the norm, so this backs that up. Now the question is, is the size of the unit enough to warrant the time spent. If we can deduce that 10% is the norm, we need an equasion that gives the dollar per hour that one wishes to maintain based on the initial weight of the transformer.
That is your assignment for tomorrow. I am thinking that the time involved versus money earned will somewhat follow the same scale as the size of the transformer. This could be interesting.
Say a 5 ounce transformer takes 1/2 the time as a 5 pound transformer which is 10 times the reward rather than just double. I think we need some more data on this.
I love this stuff. Math, physics, and economics. COOL! Keep going teach. We need more info.
Yep, there is still more work to do here. We also need to adjust any break down for the loss of weight during breakdown. Pullling out glue, paper, loss of metal dust, etc. and then, as you suggested, account for the implicit costs of time.
After that, we need some expiermentation to calculate the average weight of copper in a 1, 5, 10, 20 pound transformer. Maybe we can all chip in to do this. I have 5 different 10 pound transformers that i can find the average. Anyone have 5 different 1 pound, 5pound & 20 pound tranfromers they would be willing to break down and weigh?
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