Originally Posted by
Jeremiah
Not sure why you would think the percentages would be the same for a break even point? The copper/steel ratio may be the same, as this is really a function of transformer type and various transformers may yield various copper/steel ratios. None of this has to do with your break even point. The math is correct.
You would have to elaborate the rest of your post. My statistics is very solid as my graduate studies were in probability and econometrics but I'm not sure why you would want to incorporate a dimensionaliss variable like pi into a model about weight
Not that it is that important but, I would have to agree with Amnelson. I believe that math on the bottom of your comment is incorrect where it says:
"1 Pound Transformer = .67% or .0067 pounds of copper
5 Pound Transformer = 3.38% or .338 pounds of copper
10 Pound transformer = 6.76% or .676 pounds of copper
20 Pound Transformer = 13.5% or 1.35 pounds of copper"
.0067 is incorrect for the pounds of copper in the 1 pound transformer. I think you meant to put .067 lbs. All of the percentages are incorrect except for the 10lb transformer. So, everything looked right that you wrote except the last portion at the end and correct me if I'm wrong. Oh and your last comment you spelled "your" when I think you meant "you're".
Good thing this is a web forum and things dont have to be exact. I make similar mistakes all the time.
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