Originally Posted by
PartTimeScrapper
Ok your own math doesn't add up. You said 78 mylars were aprox a pound and that pound would yield 12 to 15 grams of silver. So if we take 12grams and devide that by 78 mylars you get .15 grams of silver per mylar not .05 Also I went out back and weighed the mylars I had taken out from random keyboard and I get closer to 50 mylars per pound.
Averages my friend. Averages. Take the same keyboard mylars (if you have them) and get a total of 1 lb. Once you get 1 lb of them, count how many you have. You'll have between 70 - 84 keyboards. From all the mylars I've processed and weighed, the average amount of the SAME mylars is 78 sheets.
I just now took random mylars from my pile and weighed them to 1 lb. From the random sheets I weighed, I came up with 60 sheets. So, right now, it looks like there are on average, counting 60 and your 50, we can say there's an average of 55 mylars per lb of random mylars.
So, my math has been based on the same exact sheets and not random sheets. I'll do more random sheets and see what I average from doing it that way. But, as I mentioned before, you'll get an average of 78 sheets per lb using the same exact mylars.
As far as the amount of silver per mylar, your math would be correct. I used the data from another source where refining is discussed. I'll go back and review the data again and if needed, ask them to make a correction to the amount listed. That would mean that 50 mylars will yield 0.24 - 0.3 grams per mylar at 12 - 15 grams total.
I'll recheck those numbers again to make sure, but the data per mylar isn't on the top of the data chart. I'm interested in what is actually recovered per lb. From there an average per mylar can be better calculated.
Since I have plenty of mylars, I'm going to weigh more random mylars to see the weights of them, and I'll do some more of the same mylars (I did 4 separate lbs already) to get more weight data.
Thanks for the input. I'll go recheck my other source to make sure I'm not calculating incorrectly.
Kevin
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